(X+1)+(x+2)+(4x+3)=48

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Solution for (X+1)+(x+2)+(4x+3)=48 equation:


Simplifying
(X + 1) + (x + 2) + (4x + 3) = 48

Reorder the terms:
(1 + X) + (x + 2) + (4x + 3) = 48

Remove parenthesis around (1 + X)
1 + X + (x + 2) + (4x + 3) = 48

Reorder the terms:
1 + X + (2 + x) + (4x + 3) = 48

Remove parenthesis around (2 + x)
1 + X + 2 + x + (4x + 3) = 48

Reorder the terms:
1 + X + 2 + x + (3 + 4x) = 48

Remove parenthesis around (3 + 4x)
1 + X + 2 + x + 3 + 4x = 48

Reorder the terms:
1 + 2 + 3 + X + x + 4x = 48

Combine like terms: 1 + 2 = 3
3 + 3 + X + x + 4x = 48

Combine like terms: 3 + 3 = 6
6 + X + x + 4x = 48

Combine like terms: x + 4x = 5x
6 + X + 5x = 48

Solving
6 + X + 5x = 48

Solving for variable 'X'.

Move all terms containing X to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + X + -6 + 5x = 48 + -6

Reorder the terms:
6 + -6 + X + 5x = 48 + -6

Combine like terms: 6 + -6 = 0
0 + X + 5x = 48 + -6
X + 5x = 48 + -6

Combine like terms: 48 + -6 = 42
X + 5x = 42

Add '-5x' to each side of the equation.
X + 5x + -5x = 42 + -5x

Combine like terms: 5x + -5x = 0
X + 0 = 42 + -5x
X = 42 + -5x

Simplifying
X = 42 + -5x

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