(X+1)/2=(2x-4)/3

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Solution for (X+1)/2=(2x-4)/3 equation: 



(X+1)/2=(2X-4)/3

We move all terms to the left:

(X+1)/2-((2X-4)/3)=0

We calculate fractions


X/()+(-((2X-4)*2)/()=0



We calculate terms in parentheses: +(-((2X-4)*2)/(), so:

-((2X-4)*2)/(

We multiply all the terms by the denominator


-((2X-4)*2)



We calculate terms in parentheses: -((2X-4)*2), so:

(2X-4)*2

We multiply parentheses

4X-8

Back to the equation:

-(4X-8)



We get rid of parentheses

-4X+8

Back to the equation:

+(-4X+8)



We get rid of parentheses

X/()-4X+8=0

We multiply all the terms by the denominator


X-4X*()+8*()=0

We add all the numbers together, and all the variables

X-4X*()=0

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