(X+1)/2=(x-1)/3+1

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Solution for (X+1)/2=(x-1)/3+1 equation: 



(X+1)/2=(X-1)/3+1

We move all terms to the left:

(X+1)/2-((X-1)/3+1)=0

We calculate fractions


(3X+3)/()+(-((X-1)*2)/()=0



We calculate terms in parentheses: +(-((X-1)*2)/(), so:

-((X-1)*2)/(

We multiply all the terms by the denominator


-((X-1)*2)



We calculate terms in parentheses: -((X-1)*2), so:

(X-1)*2

We multiply parentheses

2X-2

Back to the equation:

-(2X-2)



We get rid of parentheses

-2X+2

Back to the equation:

+(-2X+2)



We get rid of parentheses

(3X+3)/()-2X+2=0

We multiply all the terms by the denominator


(3X+3)-2X*()+2*()=0

We add all the numbers together, and all the variables

(3X+3)-2X*()=0

We get rid of parentheses

3X-2X*()+3=0

We move all terms containing X to the left, all other terms to the right

3X-2X*()=-3

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