(X+1)/3=(2x-3)/7

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Solution for (X+1)/3=(2x-3)/7 equation: 



(X+1)/3=(2X-3)/7

We move all terms to the left:

(X+1)/3-((2X-3)/7)=0

We calculate fractions


X/()+(-((2X-3)*3)/()=0



We calculate terms in parentheses: +(-((2X-3)*3)/(), so:

-((2X-3)*3)/(

We multiply all the terms by the denominator


-((2X-3)*3)



We calculate terms in parentheses: -((2X-3)*3), so:

(2X-3)*3

We multiply parentheses

6X-9

Back to the equation:

-(6X-9)



We get rid of parentheses

-6X+9

Back to the equation:

+(-6X+9)



We get rid of parentheses

X/()-6X+9=0

We multiply all the terms by the denominator


X-6X*()+9*()=0

We add all the numbers together, and all the variables

X-6X*()=0

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