(X+10)(x+14)=(x-20)

Solution for (X+10)(x+14)=(x-20) equation:

(X+10)(X+14)=(X-20)

We move all terms to the left:

(X+10)(X+14)-((X-20))=0

We multiply parentheses ..

(+X^2+14X+10X+140)-((X-20))=0


We calculate terms in parentheses: -((X-20)), so:

(X-20)

We get rid of parentheses

X-20

Back to the equation:

-(X-20)


We get rid of parentheses

X^2+14X+10X-X+140+20=0

We add all the numbers together, and all the variables

X^2+23X+160=0

a = 1; b = 23; c = +160;
Δ = b2-4ac
Δ = 232-4·1·160
Δ = -111
Delta is less than zero, so there is no solution for the equation