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(X+10)(X+15)=0
We multiply parentheses ..
(+X^2+15X+10X+150)=0
We get rid of parentheses
X^2+15X+10X+150=0
We add all the numbers together, and all the variables
X^2+25X+150=0
a = 1; b = 25; c = +150;
Δ = b2-4ac
Δ = 252-4·1·150
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-5}{2*1}=\frac{-30}{2} =-15 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+5}{2*1}=\frac{-20}{2} =-10 $
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