(X+11)(x+11)=104

Solution for (X+11)(x+11)=104 equation:

(X+11)(X+11)=104

We move all terms to the left:

(X+11)(X+11)-(104)=0

We multiply parentheses ..

(+X^2+11X+11X+121)-104=0

We get rid of parentheses

X^2+11X+11X+121-104=0

We add all the numbers together, and all the variables

X^2+22X+17=0

a = 1; b = 22; c = +17;
Δ = b2-4ac
Δ = 222-4·1·17
Δ = 416
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{416}=\sqrt{16*26}=\sqrt{16}*\sqrt{26}=4\sqrt{26}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-4\sqrt{26}}{2*1}=\frac{-22-4\sqrt{26}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+4\sqrt{26}}{2*1}=\frac{-22+4\sqrt{26}}{2}
$