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(X+15)(X+10)=150
We move all terms to the left:
(X+15)(X+10)-(150)=0
We multiply parentheses ..
(+X^2+10X+15X+150)-150=0
We get rid of parentheses
X^2+10X+15X+150-150=0
We add all the numbers together, and all the variables
X^2+25X=0
a = 1; b = 25; c = 0;
Δ = b2-4ac
Δ = 252-4·1·0
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-25}{2*1}=\frac{-50}{2} =-25 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+25}{2*1}=\frac{0}{2} =0 $
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