(X+2)(2x-4)=(2x-1)x

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Solution for (X+2)(2x-4)=(2x-1)x equation: 



(X+2)(2X-4)=(2X-1)X

We move all terms to the left:

(X+2)(2X-4)-((2X-1)X)=0

We multiply parentheses ..

(+2X^2-4X+4X-8)-((2X-1)X)=0



We calculate terms in parentheses: -((2X-1)X), so:

(2X-1)X

We multiply parentheses

2X^2-1X

Back to the equation:

-(2X^2-1X)



We get rid of parentheses

2X^2-2X^2-4X+4X+1X-8=0

We add all the numbers together, and all the variables

X-8=0

We move all terms containing X to the left, all other terms to the right

X=8

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