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(X+2)(5+5X)=0
We add all the numbers together, and all the variables
(X+2)(5X+5)=0
We multiply parentheses ..
(+5X^2+5X+10X+10)=0
We get rid of parentheses
5X^2+5X+10X+10=0
We add all the numbers together, and all the variables
5X^2+15X+10=0
a = 5; b = 15; c = +10;
Δ = b2-4ac
Δ = 152-4·5·10
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-5}{2*5}=\frac{-20}{10} =-2 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+5}{2*5}=\frac{-10}{10} =-1 $
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