(X+2)(x+2+x/2)=88

Solution for (X+2)(x+2+x/2)=88 equation:

(X+2)(X+2+X/2)=88

We move all terms to the left:

(X+2)(X+2+X/2)-(88)=0

We add all the numbers together, and all the variables

(X+2)(X+X/2+2)-88=0

We multiply parentheses ..

(+X^2+X^2+2X+2X+2X+4)-88=0

We get rid of parentheses

X^2+X^2+2X+2X+2X+4-88=0

We add all the numbers together, and all the variables

2X^2+6X-84=0

a = 2; b = 6; c = -84;
Δ = b2-4ac
Δ = 62-4·2·(-84)
Δ = 708
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{708}=\sqrt{4*177}=\sqrt{4}*\sqrt{177}=2\sqrt{177}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{177}}{2*2}=\frac{-6-2\sqrt{177}}{4}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{177}}{2*2}=\frac{-6+2\sqrt{177}}{4}
$