(X+2)(x+3)+(x-3)(x-2)-2x(x-1)=0

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Solution for (X+2)(x+3)+(x-3)(x-2)-2x(x-1)=0 equation: 



(X+2)(X+3)+(X-3)(X-2)-2X(X-1)=0

We multiply parentheses

-2X^2+(X+2)(X+3)+(X-3)(X-2)+2X=0

We multiply parentheses ..

-2X^2+(+X^2+3X+2X+6)+(X-3)(X-2)+2X=0

We add all the numbers together, and all the variables

-2X^2+(+X^2+3X+2X+6)+2X+(X-3)(X-2)=0

We get rid of parentheses

-2X^2+X^2+3X+2X+2X+(X-3)(X-2)+6=0

We multiply parentheses ..

-2X^2+X^2+(+X^2-2X-3X+6)+3X+2X+2X+6=0

We add all the numbers together, and all the variables

-1X^2+(+X^2-2X-3X+6)+7X+6=0

We get rid of parentheses

-1X^2+X^2-2X-3X+7X+6+6=0

We add all the numbers together, and all the variables

2X+12=0

We move all terms containing X to the left, all other terms to the right

2X=-12

X=-12/2

X=-6

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