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(X+2)(X-1)=-10
We move all terms to the left:
(X+2)(X-1)-(-10)=0
We add all the numbers together, and all the variables
(X+2)(X-1)+10=0
We multiply parentheses ..
(+X^2-1X+2X-2)+10=0
We get rid of parentheses
X^2-1X+2X-2+10=0
We add all the numbers together, and all the variables
X^2+X+8=0
a = 1; b = 1; c = +8;
Δ = b2-4ac
Δ = 12-4·1·8
Δ = -31
Delta is less than zero, so there is no solution for the equation
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