(X+2)(x-3)=(x-3)(x+2)

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Solution for (X+2)(x-3)=(x-3)(x+2) equation: 



(X+2)(X-3)=(X-3)(X+2)

We move all terms to the left:

(X+2)(X-3)-((X-3)(X+2))=0

We multiply parentheses ..

(+X^2-3X+2X-6)-((X-3)(X+2))=0



We calculate terms in parentheses: -((X-3)(X+2)), so:

(X-3)(X+2)

We multiply parentheses ..

(+X^2+2X-3X-6)

We get rid of parentheses

X^2+2X-3X-6

We add all the numbers together, and all the variables

X^2-1X-6

Back to the equation:

-(X^2-1X-6)



We get rid of parentheses

X^2-X^2-3X+2X+1X-6+6=0

We add all the numbers together, and all the variables

=0

X=0/1

X=0

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