(X+2)(x-4)=(x-3)(x+1)

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Solution for (X+2)(x-4)=(x-3)(x+1) equation: 



(X+2)(X-4)=(X-3)(X+1)

We move all terms to the left:

(X+2)(X-4)-((X-3)(X+1))=0

We multiply parentheses ..

(+X^2-4X+2X-8)-((X-3)(X+1))=0



We calculate terms in parentheses: -((X-3)(X+1)), so:

(X-3)(X+1)

We multiply parentheses ..

(+X^2+X-3X-3)

We get rid of parentheses

X^2+X-3X-3

We add all the numbers together, and all the variables

X^2-2X-3

Back to the equation:

-(X^2-2X-3)



We get rid of parentheses

X^2-X^2-4X+2X+2X-8+3=0

We add all the numbers together, and all the variables

-5!=0

There is no solution for this equation

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