(X+2)(x-5)=(x+1)(x-3)

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Solution for (X+2)(x-5)=(x+1)(x-3) equation: 



(X+2)(X-5)=(X+1)(X-3)

We move all terms to the left:

(X+2)(X-5)-((X+1)(X-3))=0

We multiply parentheses ..

(+X^2-5X+2X-10)-((X+1)(X-3))=0



We calculate terms in parentheses: -((X+1)(X-3)), so:

(X+1)(X-3)

We multiply parentheses ..

(+X^2-3X+X-3)

We get rid of parentheses

X^2-3X+X-3

We add all the numbers together, and all the variables

X^2-2X-3

Back to the equation:

-(X^2-2X-3)



We get rid of parentheses

X^2-X^2-5X+2X+2X-10+3=0

We add all the numbers together, and all the variables

-1X-7=0

We move all terms containing X to the left, all other terms to the right

-X=7

X=7/-1

X=-7

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