(X+2)+2(x+3)=3(x+1)+x

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Solution for (X+2)+2(x+3)=3(x+1)+x equation: 



(X+2)+2(X+3)=3(X+1)+X

We move all terms to the left:

(X+2)+2(X+3)-(3(X+1)+X)=0

We multiply parentheses

(X+2)+2X-(3(X+1)+X)+6=0

We get rid of parentheses

X+2X-(3(X+1)+X)+2+6=0



We calculate terms in parentheses: -(3(X+1)+X), so:

3(X+1)+X

We add all the numbers together, and all the variables

X+3(X+1)

We multiply parentheses

X+3X+3

We add all the numbers together, and all the variables

4X+3

Back to the equation:

-(4X+3)



We add all the numbers together, and all the variables

3X-(4X+3)+8=0

We get rid of parentheses

3X-4X-3+8=0

We add all the numbers together, and all the variables

-1X+5=0

We move all terms containing X to the left, all other terms to the right

-X=-5

X=-5/-1

X=+5

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