(X+2)+2x-4=8(x-2)+8

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Solution for (X+2)+2x-4=8(x-2)+8 equation: 



(X+2)+2X-4=8(X-2)+8

We move all terms to the left:

(X+2)+2X-4-(8(X-2)+8)=0

We add all the numbers together, and all the variables

2X+(X+2)-(8(X-2)+8)-4=0

We get rid of parentheses

2X+X-(8(X-2)+8)+2-4=0



We calculate terms in parentheses: -(8(X-2)+8), so:

8(X-2)+8

We multiply parentheses

8X-16+8

We add all the numbers together, and all the variables

8X-8

Back to the equation:

-(8X-8)



We add all the numbers together, and all the variables

3X-(8X-8)-2=0

We get rid of parentheses

3X-8X+8-2=0

We add all the numbers together, and all the variables

-5X+6=0

We move all terms containing X to the left, all other terms to the right

-5X=-6

X=-6/-5

X=1+1/5

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