(X+2)/2=10-(x+5)/3

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Solution for (X+2)/2=10-(x+5)/3 equation: 



(X+2)/2=10-(X+5)/3

We move all terms to the left:

(X+2)/2-(10-(X+5)/3)=0

We calculate fractions


X/()+(-(10-(X+5)*2)/()=0



We calculate terms in parentheses: +(-(10-(X+5)*2)/(), so:

-(10-(X+5)*2)/(

We multiply all the terms by the denominator


-(10-(X+5)*2)



We calculate terms in parentheses: -(10-(X+5)*2), so:

10-(X+5)*2

determiningTheFunctionDomain
-(X+5)*2+10

We multiply parentheses

-2X-10+10

We add all the numbers together, and all the variables

-2X

Back to the equation:

-(-2X)



We get rid of parentheses

2X

Back to the equation:

+(2X)



We add all the numbers together, and all the variables

2X+X/()=0

We multiply all the terms by the denominator


2X*()+X=0

We add all the numbers together, and all the variables

X+2X*()=0

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