(X+2)/2=3-(x+1)/7

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Solution for (X+2)/2=3-(x+1)/7 equation: 



(X+2)/2=3-(X+1)/7

We move all terms to the left:

(X+2)/2-(3-(X+1)/7)=0

We calculate fractions


X/()+(-(3-(X+1)*2)/()=0



We calculate terms in parentheses: +(-(3-(X+1)*2)/(), so:

-(3-(X+1)*2)/(

We multiply all the terms by the denominator


-(3-(X+1)*2)



We calculate terms in parentheses: -(3-(X+1)*2), so:

3-(X+1)*2

determiningTheFunctionDomain
-(X+1)*2+3

We multiply parentheses

-2X-2+3

We add all the numbers together, and all the variables

-2X+1

Back to the equation:

-(-2X+1)



We get rid of parentheses

2X-1

Back to the equation:

+(2X-1)



We get rid of parentheses

X/()+2X-1=0

We multiply all the terms by the denominator


X+2X*()-1*()=0

We add all the numbers together, and all the variables

X+2X*()=0

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