(X+2)/3=(-3x-6)/6

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Solution for (X+2)/3=(-3x-6)/6 equation: 



(X+2)/3=(-3X-6)/6

We move all terms to the left:

(X+2)/3-((-3X-6)/6)=0

We calculate fractions


X/()+(-((-3X-6)*3)/()=0



We calculate terms in parentheses: +(-((-3X-6)*3)/(), so:

-((-3X-6)*3)/(

We multiply all the terms by the denominator


-((-3X-6)*3)



We calculate terms in parentheses: -((-3X-6)*3), so:

(-3X-6)*3

We multiply parentheses

-9X-18

Back to the equation:

-(-9X-18)



We get rid of parentheses

9X+18

Back to the equation:

+(9X+18)



We get rid of parentheses

X/()+9X+18=0

We multiply all the terms by the denominator


X+9X*()+18*()=0

We add all the numbers together, and all the variables

X+9X*()=0

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