(X+2)/3=3-(x+5)/2

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Solution for (X+2)/3=3-(x+5)/2 equation: 



(X+2)/3=3-(X+5)/2

We move all terms to the left:

(X+2)/3-(3-(X+5)/2)=0

We calculate fractions


X/()+(-(3-(X+5)*3)/()=0



We calculate terms in parentheses: +(-(3-(X+5)*3)/(), so:

-(3-(X+5)*3)/(

We multiply all the terms by the denominator


-(3-(X+5)*3)



We calculate terms in parentheses: -(3-(X+5)*3), so:

3-(X+5)*3

determiningTheFunctionDomain
-(X+5)*3+3

We multiply parentheses

-3X-15+3

We add all the numbers together, and all the variables

-3X-12

Back to the equation:

-(-3X-12)



We get rid of parentheses

3X+12

Back to the equation:

+(3X+12)



We get rid of parentheses

X/()+3X+12=0

We multiply all the terms by the denominator


X+3X*()+12*()=0

We add all the numbers together, and all the variables

X+3X*()=0

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