(X+2)/5=(x+3)/7

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Solution for (X+2)/5=(x+3)/7 equation: 



(X+2)/5=(X+3)/7

We move all terms to the left:

(X+2)/5-((X+3)/7)=0

We calculate fractions


X/()+(-((X+3)*5)/()=0



We calculate terms in parentheses: +(-((X+3)*5)/(), so:

-((X+3)*5)/(

We multiply all the terms by the denominator


-((X+3)*5)



We calculate terms in parentheses: -((X+3)*5), so:

(X+3)*5

We multiply parentheses

5X+15

Back to the equation:

-(5X+15)



We get rid of parentheses

-5X-15

Back to the equation:

+(-5X-15)



We get rid of parentheses

X/()-5X-15=0

We multiply all the terms by the denominator


X-5X*()-15*()=0

We add all the numbers together, and all the variables

X-5X*()=0

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