(X+2)/6=(3x-5)/3

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Solution for (X+2)/6=(3x-5)/3 equation: 



(X+2)/6=(3X-5)/3

We move all terms to the left:

(X+2)/6-((3X-5)/3)=0

We calculate fractions


X/()+(-((3X-5)*6)/()=0



We calculate terms in parentheses: +(-((3X-5)*6)/(), so:

-((3X-5)*6)/(

We multiply all the terms by the denominator


-((3X-5)*6)



We calculate terms in parentheses: -((3X-5)*6), so:

(3X-5)*6

We multiply parentheses

18X-30

Back to the equation:

-(18X-30)



We get rid of parentheses

-18X+30

Back to the equation:

+(-18X+30)



We get rid of parentheses

X/()-18X+30=0

We multiply all the terms by the denominator


X-18X*()+30*()=0

We add all the numbers together, and all the variables

X-18X*()=0

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