(X+2)2+(y+1)2=13

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Solution for (X+2)2+(y+1)2=13 equation: 


Simplifying
(X + 2) * 2 + (y + 1) * 2 = 13

Reorder the terms:
(2 + X) * 2 + (y + 1) * 2 = 13

Reorder the terms for easier multiplication:
2(2 + X) + (y + 1) * 2 = 13
(2 * 2 + X * 2) + (y + 1) * 2 = 13
(4 + 2X) + (y + 1) * 2 = 13

Reorder the terms:
4 + 2X + (1 + y) * 2 = 13

Reorder the terms for easier multiplication:
4 + 2X + 2(1 + y) = 13
4 + 2X + (1 * 2 + y * 2) = 13
4 + 2X + (2 + 2y) = 13

Reorder the terms:
4 + 2 + 2X + 2y = 13

Combine like terms: 4 + 2 = 6
6 + 2X + 2y = 13

Solving
6 + 2X + 2y = 13

Solving for variable 'X'.

Move all terms containing X to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + 2X + -6 + 2y = 13 + -6

Reorder the terms:
6 + -6 + 2X + 2y = 13 + -6

Combine like terms: 6 + -6 = 0
0 + 2X + 2y = 13 + -6
2X + 2y = 13 + -6

Combine like terms: 13 + -6 = 7
2X + 2y = 7

Add '-2y' to each side of the equation.
2X + 2y + -2y = 7 + -2y

Combine like terms: 2y + -2y = 0
2X + 0 = 7 + -2y
2X = 7 + -2y

Divide each side by '2'.
X = 3.5 + -1y

Simplifying
X = 3.5 + -1y

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