(X+2)x=x+x-4x(x+2)

Solution for (X+2)x=x+x-4x(x+2) equation:

(X+2)X=X+X-4X(X+2)

We move all terms to the left:

(X+2)X-(X+X-4X(X+2))=0

We multiply parentheses

X^2+2X-(X+X-4X(X+2))=0


We calculate terms in parentheses: -(X+X-4X(X+2)), so:

X+X-4X(X+2)

We add all the numbers together, and all the variables

2X-4X(X+2)

We multiply parentheses

-4X^2+2X-8X

We add all the numbers together, and all the variables

-4X^2-6X

Back to the equation:

-(-4X^2-6X)


We get rid of parentheses

X^2+4X^2+6X+2X=0

We add all the numbers together, and all the variables

5X^2+8X=0

a = 5; b = 8; c = 0;
Δ = b2-4ac
Δ = 82-4·5·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-8}{2*5}=\frac{-16}{10}
=-1+3/5
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+8}{2*5}=\frac{0}{10}
=0
$