(X+3)(2x+2)=(2x+2)=(2x-1)(x+5)-2

Solution for (X+3)(2x+2)=(2x+2)=(2x-1)(x+5)-2 equation:

(X+3)(2X+2)=(2X+2)=(2X-1)(X+5)-2

We move all terms to the left:

(X+3)(2X+2)-((2X+2))=0

We multiply parentheses ..

(+2X^2+2X+6X+6)-((2X+2))=0


We calculate terms in parentheses: -((2X+2)), so:

(2X+2)

We get rid of parentheses

2X+2

Back to the equation:

-(2X+2)


We get rid of parentheses

2X^2+2X+6X-2X+6-2=0

We add all the numbers together, and all the variables

2X^2+6X+4=0

a = 2; b = 6; c = +4;
Δ = b2-4ac
Δ = 62-4·2·4
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2}{2*2}=\frac{-8}{4}
=-2
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2}{2*2}=\frac{-4}{4}
=-1
$