(X+3)(2x+2)=(2x-1)(x+5)-2

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Solution for (X+3)(2x+2)=(2x-1)(x+5)-2 equation:



(X+3)(2X+2)=(2X-1)(X+5)-2
We move all terms to the left:
(X+3)(2X+2)-((2X-1)(X+5)-2)=0
We multiply parentheses ..
(+2X^2+2X+6X+6)-((2X-1)(X+5)-2)=0
We calculate terms in parentheses: -((2X-1)(X+5)-2), so:
(2X-1)(X+5)-2
We multiply parentheses ..
(+2X^2+10X-1X-5)-2
We get rid of parentheses
2X^2+10X-1X-5-2
We add all the numbers together, and all the variables
2X^2+9X-7
Back to the equation:
-(2X^2+9X-7)
We get rid of parentheses
2X^2-2X^2+2X+6X-9X+6+7=0
We add all the numbers together, and all the variables
-1X+13=0
We move all terms containing X to the left, all other terms to the right
-X=-13
X=-13/-1
X=+13

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