(X+3)(x+3)=(x-4)(x+4)

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Solution for (X+3)(x+3)=(x-4)(x+4) equation: 



(X+3)(X+3)=(X-4)(X+4)

We move all terms to the left:

(X+3)(X+3)-((X-4)(X+4))=0

We use the square of the difference formula

X^2+(X+3)(X+3)+16=0

We multiply parentheses ..

X^2+(+X^2+3X+3X+9)+16=0

We get rid of parentheses

X^2+X^2+3X+3X+9+16=0

We add all the numbers together, and all the variables

2X^2+6X+25=0

a = 2; b = 6; c = +25;
Δ = b2-4ac
Δ = 62-4·2·25
Δ = -164
Delta is less than zero, so there is no solution for the equation

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