(X+3)(x+4)=x+7(x-2)

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Solution for (X+3)(x+4)=x+7(x-2) equation:



(X+3)(X+4)=X+7(X-2)
We move all terms to the left:
(X+3)(X+4)-(X+7(X-2))=0
We multiply parentheses ..
(+X^2+4X+3X+12)-(X+7(X-2))=0
We calculate terms in parentheses: -(X+7(X-2)), so:
X+7(X-2)
We multiply parentheses
X+7X-14
We add all the numbers together, and all the variables
8X-14
Back to the equation:
-(8X-14)
We get rid of parentheses
X^2+4X+3X-8X+12+14=0
We add all the numbers together, and all the variables
X^2-1X+26=0
a = 1; b = -1; c = +26;
Δ = b2-4ac
Δ = -12-4·1·26
Δ = -103
Delta is less than zero, so there is no solution for the equation

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