(X+3)(x+7)=-(x-3)(x-4)

Solution for (X+3)(x+7)=-(x-3)(x-4) equation:

(X+3)(X+7)=-(X-3)(X-4)

We move all terms to the left:

(X+3)(X+7)-(-(X-3)(X-4))=0

We multiply parentheses ..

(+X^2+7X+3X+21)-(-(X-3)(X-4))=0


We calculate terms in parentheses: -(-(X-3)(X-4)), so:

-(X-3)(X-4)

We multiply parentheses ..

-(+X^2-4X-3X+12)

We get rid of parentheses

-X^2+4X+3X-12

We add all the numbers together, and all the variables

-1X^2+7X-12

Back to the equation:

-(-1X^2+7X-12)


We get rid of parentheses

X^2+1X^2+7X+3X-7X+21+12=0

We add all the numbers together, and all the variables

2X^2+3X+33=0

a = 2; b = 3; c = +33;
Δ = b2-4ac
Δ = 32-4·2·33
Δ = -255
Delta is less than zero, so there is no solution for the equation