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(X+3)(X-2)=(X-7)(X+4)
We move all terms to the left:
(X+3)(X-2)-((X-7)(X+4))=0
We multiply parentheses ..
(+X^2-2X+3X-6)-((X-7)(X+4))=0
We calculate terms in parentheses: -((X-7)(X+4)), so:We get rid of parentheses
(X-7)(X+4)
We multiply parentheses ..
(+X^2+4X-7X-28)
We get rid of parentheses
X^2+4X-7X-28
We add all the numbers together, and all the variables
X^2-3X-28
Back to the equation:
-(X^2-3X-28)
X^2-X^2-2X+3X+3X-6+28=0
We add all the numbers together, and all the variables
4X+22=0
We move all terms containing X to the left, all other terms to the right
4X=-22
X=-22/4
X=-5+1/2
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