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(X+3)/X+2=(X+5)/X
We move all terms to the left:
(X+3)/X+2-((X+5)/X)=0
Domain of the equation: X!=0
X∈R
Domain of the equation: X)!=0We calculate fractions
X!=0/1
X!=0
X∈R
(X+3)*X)/X^2+(-((X+5)*X)/X^2+2=0
We calculate fractions
((X+3)*X)*X^2)/(X^2+(*X^2)+(-((X+5)*X)*X^2)/(X^2+(*X^2)+2=0
We get rid of parentheses
((X+3)*X)*X^2)/(X^2+*X^2+(-((X+5)*X)*X^2)/(X^2+(*X^2)+2=0
We calculate fractions
*X^2+(X^2+((X+3)*X)*X^2)*(X^2+2)/((X^2*(X^2+(*X^2)+2)+((-((X+5)*X)*X^2)*X^2/((X^2*(X^2+(*X^2)+2)=0
We calculate terms in parentheses: +(X^2+((X+3)*X)*X^2)*(X^2+2)/((X^2*(X^2+(*X^2)+2)+((-((X+5)*X)*X^2)*X^2/((X^2*(X^2+(*X^2)+2), so:
X^2+((X+3)*X)*X^2)*(X^2+2)/((X^2*(X^2+(*X^2)+2)+((-((X+5)*X)*X^2)*X^2/((X^2*(X^2+(*X^2)+2
We can not solve this equation
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