(X+3)2=16+(x+1)(x-1)

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Solution for (X+3)2=16+(x+1)(x-1) equation: 



(X+3)2=16+(X+1)(X-1)

We move all terms to the left:

(X+3)2-(16+(X+1)(X-1))=0

We use the square of the difference formula

X^2+(X+3)2+1=0

We multiply parentheses

X^2+2X+6+1=0

We add all the numbers together, and all the variables

X^2+2X+7=0

a = 1; b = 2; c = +7;
Δ = b2-4ac
Δ = 22-4·1·7
Δ = -24
Delta is less than zero, so there is no solution for the equation

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