(X+4)(x)/2=14

Solution for (X+4)(x)/2=14 equation:

(X+4)(X)/2=14

We move all terms to the left:

(X+4)(X)/2-(14)=0

We multiply all the terms by the denominator


(X+4)X-14*2=0

We add all the numbers together, and all the variables

(X+4)X-28=0

We multiply parentheses

X^2+4X-28=0

a = 1; b = 4; c = -28;
Δ = b2-4ac
Δ = 42-4·1·(-28)
Δ = 128
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{128}=\sqrt{64*2}=\sqrt{64}*\sqrt{2}=8\sqrt{2}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-8\sqrt{2}}{2*1}=\frac{-4-8\sqrt{2}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+8\sqrt{2}}{2*1}=\frac{-4+8\sqrt{2}}{2}
$