(X+4)(x*1)=x(x+1)+12

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Solution for (X+4)(x*1)=x(x+1)+12 equation: 



(X+4)(X*1)=X(X+1)+12

We move all terms to the left:

(X+4)(X*1)-(X(X+1)+12)=0

We add all the numbers together, and all the variables

(X+4)(+X*1)-(X(X+1)+12)=0

We multiply parentheses ..

(+X^2+4X)-(X(X+1)+12)=0



We calculate terms in parentheses: -(X(X+1)+12), so:

X(X+1)+12

We multiply parentheses

X^2+X+12

Back to the equation:

-(X^2+X+12)



We get rid of parentheses

X^2-X^2+4X-X-12=0

We add all the numbers together, and all the variables

3X-12=0

We move all terms containing X to the left, all other terms to the right

3X=12

X=12/3

X=4

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