(X+4)(x-3)=44

Solution for (X+4)(x-3)=44 equation:

(X+4)(X-3)=44

We move all terms to the left:

(X+4)(X-3)-(44)=0

We multiply parentheses ..

(+X^2-3X+4X-12)-44=0

We get rid of parentheses

X^2-3X+4X-12-44=0

We add all the numbers together, and all the variables

X^2+X-56=0

a = 1; b = 1; c = -56;
Δ = b2-4ac
Δ = 12-4·1·(-56)
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-15}{2*1}=\frac{-16}{2}
=-8
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+15}{2*1}=\frac{14}{2}
=7
$