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(X+4)(X-6)=3X
We move all terms to the left:
(X+4)(X-6)-(3X)=0
We add all the numbers together, and all the variables
-3X+(X+4)(X-6)=0
We multiply parentheses ..
(+X^2-6X+4X-24)-3X=0
We get rid of parentheses
X^2-6X+4X-3X-24=0
We add all the numbers together, and all the variables
X^2-5X-24=0
a = 1; b = -5; c = -24;
Δ = b2-4ac
Δ = -52-4·1·(-24)
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{121}=11$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-11}{2*1}=\frac{-6}{2} =-3 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+11}{2*1}=\frac{16}{2} =8 $
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