(X+4)+(2x+1)+(3x-2)=45

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Solution for (X+4)+(2x+1)+(3x-2)=45 equation: 



(X+4)+(2X+1)+(3X-2)=45

We move all terms to the left:

(X+4)+(2X+1)+(3X-2)-(45)=0

We get rid of parentheses

X+2X+3X+4+1-2-45=0

We add all the numbers together, and all the variables

6X-42=0

We move all terms containing X to the left, all other terms to the right

6X=42

X=42/6

X=7

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