(X+4)+(3x-7)=(x-2)+(3x+8)

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Solution for (X+4)+(3x-7)=(x-2)+(3x+8) equation: 



(X+4)+(3X-7)=(X-2)+(3X+8)

We move all terms to the left:

(X+4)+(3X-7)-((X-2)+(3X+8))=0

We get rid of parentheses

X+3X-((X-2)+(3X+8))+4-7=0



We calculate terms in parentheses: -((X-2)+(3X+8)), so:

(X-2)+(3X+8)

We get rid of parentheses

X+3X-2+8

We add all the numbers together, and all the variables

4X+6

Back to the equation:

-(4X+6)



We add all the numbers together, and all the variables

4X-(4X+6)-3=0

We get rid of parentheses

4X-4X-6-3=0

We add all the numbers together, and all the variables

-9!=0

There is no solution for this equation

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