(X+4)+(x+5)+(x+2)=(x+3)+(x+3)+(x+1)+(x+1)

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Solution for (X+4)+(x+5)+(x+2)=(x+3)+(x+3)+(x+1)+(x+1) equation: 



(X+4)+(X+5)+(X+2)=(X+3)+(X+3)+(X+1)+(X+1)

We move all terms to the left:

(X+4)+(X+5)+(X+2)-((X+3)+(X+3)+(X+1)+(X+1))=0

We get rid of parentheses

X+X+X-((X+3)+(X+3)+(X+1)+(X+1))+4+5+2=0



We calculate terms in parentheses: -((X+3)+(X+3)+(X+1)+(X+1)), so:

(X+3)+(X+3)+(X+1)+(X+1)

We get rid of parentheses

X+X+X+X+3+3+1+1

We add all the numbers together, and all the variables

4X+8

Back to the equation:

-(4X+8)



We add all the numbers together, and all the variables

3X-(4X+8)+11=0

We get rid of parentheses

3X-4X-8+11=0

We add all the numbers together, and all the variables

-1X+3=0

We move all terms containing X to the left, all other terms to the right

-X=-3

X=-3/-1

X=+3

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