(X+4)/3=5-(x+3)/2

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Solution for (X+4)/3=5-(x+3)/2 equation: 



(X+4)/3=5-(X+3)/2

We move all terms to the left:

(X+4)/3-(5-(X+3)/2)=0

We calculate fractions


X/()+(-(5-(X+3)*3)/()=0



We calculate terms in parentheses: +(-(5-(X+3)*3)/(), so:

-(5-(X+3)*3)/(

We multiply all the terms by the denominator


-(5-(X+3)*3)



We calculate terms in parentheses: -(5-(X+3)*3), so:

5-(X+3)*3

determiningTheFunctionDomain
-(X+3)*3+5

We multiply parentheses

-3X-9+5

We add all the numbers together, and all the variables

-3X-4

Back to the equation:

-(-3X-4)



We get rid of parentheses

3X+4

Back to the equation:

+(3X+4)



We get rid of parentheses

X/()+3X+4=0

We multiply all the terms by the denominator


X+3X*()+4*()=0

We add all the numbers together, and all the variables

X+3X*()=0

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