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(X+5)(X)=234
We move all terms to the left:
(X+5)(X)-(234)=0
We multiply parentheses
X^2+5X-234=0
a = 1; b = 5; c = -234;
Δ = b2-4ac
Δ = 52-4·1·(-234)
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{961}=31$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-31}{2*1}=\frac{-36}{2} =-18 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+31}{2*1}=\frac{26}{2} =13 $
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