(X+5)(x+4)(x+3)=112

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Solution for (X+5)(x+4)(x+3)=112 equation:



(X+5)(X+4)(X+3)=112
We move all terms to the left:
(X+5)(X+4)(X+3)-(112)=0
We multiply parentheses ..
(+X^2+4X+5X+20)(X+3)-112=0
We move all terms containing X to the left, all other terms to the right
(+X^2+4X+5X+20)(X+3)=112

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