(X+5)(x+5)=17

Solution for (X+5)(x+5)=17 equation:

(X+5)(X+5)=17

We move all terms to the left:

(X+5)(X+5)-(17)=0

We multiply parentheses ..

(+X^2+5X+5X+25)-17=0

We get rid of parentheses

X^2+5X+5X+25-17=0

We add all the numbers together, and all the variables

X^2+10X+8=0

a = 1; b = 10; c = +8;
Δ = b2-4ac
Δ = 102-4·1·8
Δ = 68
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{68}=\sqrt{4*17}=\sqrt{4}*\sqrt{17}=2\sqrt{17}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-2\sqrt{17}}{2*1}=\frac{-10-2\sqrt{17}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+2\sqrt{17}}{2*1}=\frac{-10+2\sqrt{17}}{2}
$