(X+5)(x-8)=(x+2)(x-9)

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Solution for (X+5)(x-8)=(x+2)(x-9) equation: 



(X+5)(X-8)=(X+2)(X-9)

We move all terms to the left:

(X+5)(X-8)-((X+2)(X-9))=0

We multiply parentheses ..

(+X^2-8X+5X-40)-((X+2)(X-9))=0



We calculate terms in parentheses: -((X+2)(X-9)), so:

(X+2)(X-9)

We multiply parentheses ..

(+X^2-9X+2X-18)

We get rid of parentheses

X^2-9X+2X-18

We add all the numbers together, and all the variables

X^2-7X-18

Back to the equation:

-(X^2-7X-18)



We get rid of parentheses

X^2-X^2-8X+5X+7X-40+18=0

We add all the numbers together, and all the variables

4X-22=0

We move all terms containing X to the left, all other terms to the right

4X=22

X=22/4

X=5+1/2

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