(X+5)+(2x-3)+(3x-4)=40

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Solution for (X+5)+(2x-3)+(3x-4)=40 equation: 



(X+5)+(2X-3)+(3X-4)=40

We move all terms to the left:

(X+5)+(2X-3)+(3X-4)-(40)=0

We get rid of parentheses

X+2X+3X+5-3-4-40=0

We add all the numbers together, and all the variables

6X-42=0

We move all terms containing X to the left, all other terms to the right

6X=42

X=42/6

X=7

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