(X+5)+(3x-1)+(4x-2)=66

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Solution for (X+5)+(3x-1)+(4x-2)=66 equation: 



(X+5)+(3X-1)+(4X-2)=66

We move all terms to the left:

(X+5)+(3X-1)+(4X-2)-(66)=0

We get rid of parentheses

X+3X+4X+5-1-2-66=0

We add all the numbers together, and all the variables

8X-64=0

We move all terms containing X to the left, all other terms to the right

8X=64

X=64/8

X=8

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