(X+5)/3=2-(x+3)/8

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Solution for (X+5)/3=2-(x+3)/8 equation: 



(X+5)/3=2-(X+3)/8

We move all terms to the left:

(X+5)/3-(2-(X+3)/8)=0

We calculate fractions


X/()+(-(2-(X+3)*3)/()=0



We calculate terms in parentheses: +(-(2-(X+3)*3)/(), so:

-(2-(X+3)*3)/(

We multiply all the terms by the denominator


-(2-(X+3)*3)



We calculate terms in parentheses: -(2-(X+3)*3), so:

2-(X+3)*3

determiningTheFunctionDomain
-(X+3)*3+2

We multiply parentheses

-3X-9+2

We add all the numbers together, and all the variables

-3X-7

Back to the equation:

-(-3X-7)



We get rid of parentheses

3X+7

Back to the equation:

+(3X+7)



We get rid of parentheses

X/()+3X+7=0

We multiply all the terms by the denominator


X+3X*()+7*()=0

We add all the numbers together, and all the variables

X+3X*()=0

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