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(X+5)4X=90
We move all terms to the left:
(X+5)4X-(90)=0
We multiply parentheses
4X^2+20X-90=0
a = 4; b = 20; c = -90;
Δ = b2-4ac
Δ = 202-4·4·(-90)
Δ = 1840
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1840}=\sqrt{16*115}=\sqrt{16}*\sqrt{115}=4\sqrt{115}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-4\sqrt{115}}{2*4}=\frac{-20-4\sqrt{115}}{8} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+4\sqrt{115}}{2*4}=\frac{-20+4\sqrt{115}}{8} $
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